<aside> 💡 Rapid adiabatic passage (RAP)

$$ \left|\lambda_-\right>: \left|g\right> \rightarrow \left|e\right> \\ \Delta: -\infty \rightarrow +\infty $$

Landau-Zener probability

$$ P_{\rm LZ}=|c_g(t\rightarrow \infty)|^2 = \exp\left(-2\pi \frac{|\Omega|^2}{ 4\dot{\Delta}}\right) $$

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In the dressed state picture, the Hamiltonian under the eigenbasis is

$$ \hat{H}{\lambda} =\underbrace{\hat{U}\hat{H}{\rm RWA}\hat{U}^{\dagger}}{\rm diagonal}\underbrace{-i\hbar \hat{U}(\partial_t \hat{U}^{\dagger})}{\rm off-diagonal}= \begin{bmatrix} \lambda_+ && i\hbar\frac{\dot{\theta}}{2}\\ -i\hbar\frac{\dot{\theta}}{2} && \lambda_-\end{bmatrix} $$

If the $\dot{\theta}\rightarrow 0$, only diagonal parts survive. It means, under the condition $\dot{\theta}\rightarrow 0$ the population of the each eigenstate is trapped. This is called adiabatic theorem; the n-th eigenstate of the initial Hamiltonian evolve to the n-th eigenstate of the final Hamiltonian under the adiabatic condition where $\dot{\theta}\rightarrow 0$. More precisely, adiabatic condition is written as

$$ \Delta_{\rm gap} \gg \left|i\hbar\frac{\dot{\theta}}{2}\right| $$

where $\Delta_{\rm gap} = \left|\lambda_+-\lambda_-\right| = \hbar\sqrt{\Delta^2+\Omega^2}$.

The ground state of the Hamiltonian $\hat{H}_{\lambda}$ is

$$ \left|\lambda_-\right> = -\sin\frac{\theta}{2}\left|g\right>+\cos\frac{\theta}{2}\left|e\right> $$

If the mixing angle adiabatically ($\dot{\theta}\rightarrow 0$) change as $\theta: \pi \rightarrow 0$, the ground state is also evolve $\left|\lambda_-\right>: \left|g\right> \rightarrow \left|e\right>$. The time of adiabatic evolution ($T_{\rm adia}$, $\Delta\theta/T_{\rm adia} \ll 1$) is shorter than the lifetime of the quantum system ($T_{\rm life}$) $T_{\rm adia} \ll T_{\rm life}$, the significant probability transfer from $\left|g\right>$ to $\left|e\right>$. This kind of quantum operation is called rapid adiabatic passage (RAP).

The condition of the mixing angle $\theta: \pi \rightarrow 0$ could be re-written as $\tan\theta=\Omega/\Delta: -0 \rightarrow +0$.

Under the finite and positive Rabi frequency $\Omega > 0$, the condition of detuning is $\Delta: -\infty \rightarrow +\infty$.

By adiabatic driving, the quantum state $\left|g\right>$ is perfectly evolve to the $\left|e\right>$. If the diabatic term proportional to the $\dot{\theta}$ is significantly large so that hard to ignore, the leakage is dominant more than population trapping comes from adiabatic. So adiabatic theorem is not valid, therefore, the population of $\left|g\right>$ is not transfer to the $\left|e\right>$ but still remain at the $\left|g\right>$. It could be understood that there is a crossing from $\left|\lambda_-\right>$ to the $\left|\lambda_+\right>$. The leakage comes from diabatic transition is hard to analytically calculate in general because it has variety behavior depending on the form of $\Omega(t)$ and $\Delta(t)$. There are few analytically solved model: Landau-Zener, Allen-Eberly, etc.

(Majorana-) Landau-Zener (-Stuckelberg) ((M)LZ(S)) transition

Landau-Zener (LZ) path is one of the characteristic model of the RAP. It is simple and exactly solvable two-level system dynamics. It consist of the linear detuning sweep with constant Rabi frequency.